200W 3-Phase AC Gear Motor, Horizontal, Ratio 3~100

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$505.69

Ex Tax: $505.69

Stock: In Stock
Model: RDDLZ-GEAR-HV200
Weight: 1.00
SKU: RDDLZ-GEAR-HV200

Available Options

Rated Voltage

Gear Ratio

Installation

Terminal Box Direction

Air Hole Direction

With Brake (DC 90V)

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Low rpm 3-phase AC motor adds reduction gearbox working at 200W power. Gear ratios 3:1 to 100:1 to choose, corresponding speed rpm value 465~15, horizontal or vertical mounting direction. A brake is recommended to be used with the electric geared motor, for stopping machine safely.

Basic Specification

Model	RDDLZ-CH18-200（(Ratio:3~10) , RDDLZ-CH22-200（(Ratio:15~90), RDDLZ-CH28-200（(Ratio:100~200)
Rated Power	200W
Rated Voltage	Single-phase 110V, 50/60Hz Single-phase 220V, 50/60Hz 3-phase 220V, 50/60Hz 3-phase 380-415V, 50/60Hz
Gear Ratio	3:1/ 5:1/ 10:1/ 15:1/ 20:1/ 25:1/ 30:1/ 40:1/ 45:1/ 50:1/ 60:1/ 70:1/ 80:1/ 90:1/ 100:1
Working Efficiency	75%
Insulation Grade	Class B, Class F can be customized
Protection Grade	IP54
Duty	Continuous running
Working Environment	Temperature 10℃~+40℃ Humidity ≤90%
Pole	4P (6P)
Working Height	≤1000m
Standard	GB755/IEC-60034
Download Attachments	200W 3 Phase AC Gear Motor Datasheet

Terminal Box Direction (From Output Shaft)

AC Gear Motor Standard Installation

All the RDDLZ 3-phase AC gear motors are suitable for this installation method, as shown in the following diagram.
In the diagram, Q1, Q4, Q7, Q8 are the standard types of oil hole direction. If you need the air hole be on a special position, please contact us to modify the air hole direction.
In actual use, it is recommended to pull out the oil plug in the air hole to balance the pressure in gearbox.

Details

Tips: How to calculate torque for 3-phase AC gear motor?

After calculating the gear ratio, convert the torque using the conditions of the machine used.

First, calculate the torque of the conveyor pulley (T1)
T1 = (μ × load × roller radius) ÷ η1
Convert the result into the torque required by AC gear motor output shaft (T2)
T2 = (T1 × sprocket reduction ratio) ÷ η2

Calculation example

T1 = μ × W (D/2) ÷ η1
= 0.15 × 600 × (0.2/2) ÷ 0.95 = 9.5kgf-m
T2 = (T1 × 1/2) ÷ η2
= (9.5 × 1/2) ÷ 0.9 = 5.28kgf-m

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